Single event · Finite energy · Two models

Minimal cavitation & hydrogel models

Calculate outlet discharge and gel loading from a finite source.

Results and interpretation

Both native models use Global Equations. Model A solves two flow states and three accumulators. Model B adds two gel-wall states. The nominal 10 ns pulse is represented by post-activation initial data. Optical heating, nucleation and the activation pressure transient are excluded.

Baseline inputs: available work 2 nJ; initial gas radius 15 µm; chamber radius 30 µm; outlet radius 5 µm; effective inertance length 50 µm; density 1000 kg/m³; ambient pressure 100 kPa; adiabatic exponent 1.4. Connected chamber liquid sets the finite discharge budget. Gel inputs are G = 20 kPa and viscosity 0.010 Pa s. These inputs define the controls. PFC and hydrogel calibration remain unresolved.

Defined output Rigid chamber A Open hydrogel B
Initial chamber overpressure 279.632 kPa 279.632 kPa
Highest first-ejection outlet speed 15.37608 m/s 1.62538 m/s
Highest outlet dynamic-pressure scale 118.2119 kPa 1.3209 kPa
Emitted mass over first ejection 20.96789 ng 0.15612 ng
Emitted energy 1.391345 nJ 0.000136 nJ
Emitted impulse 2.270810e-10 N s 1.982567e-13 N s
First outward ejection duration 33.8850 µs 1.9370 µs
Largest elastic confinement pressure — 9.1430 kPa
Largest one-hemisphere elastic force — 33.7705 µN

The highest sampled outlet speed occurs in A_E5nJ_a3um: 25.27982 m/s. Source overpressure is 512.212 kPa. Outlet dynamic pressure is 319.535 kPa. The family samples work 0.5, 2 and 5 nJ. It samples outlet radii 3, 5 and 10 µm. Initial gas/chamber radii and inertance length stay fixed. These are conditional maxima within the sampled family. A universal limit is not established.

The baseline energy ceiling is 31.91538 m/s. Its dynamic-pressure ceiling is 509.296 kPa. The solution also spends energy on emission and meniscus work. Energy remains in column motion and the source. The solved maximum is therefore below these bounds.

Open-gel peak-speed transmission is 10.5709%. Emitted-energy transmission is 0.00980%. Emitted-impulse transmission is 0.08731%. Integrate outlet fluxes to obtain energy and impulse. Peak-speed ratios cannot replace those integrals. Here gel motion receives energy and shortens the first ejection. General monotonic effects of modulus and viscosity are not established.

The sealed control emits zero mass, energy and impulse. Its maximum elastic pressure is 9.6259 kPa. Its maximum inner-wall stretch is 1.15252. The gel deforms while external discharge remains zero.

The observer diagnostic bounds mean arrest pressure from emitted impulse. It uses outlet area and a 1 µs interval. Peak impact pressure is not established. Missing: contact dynamics, arriving mass, target transmission and gel fracture.

first event histories

conditional velocity envelope

energy and transmission

gel confinement

Native verification passed for all 17 cases. Maximum normalized energy residual: 1.260e-07. Maximum native/reference waveform error: 1.152e-04. Maximum pressure-communication diagnostic: 0.08356, below the stipulated 0.1 screen. Both baselines were reloaded and solved in a fresh COMSOL process. Peak velocities passed the 2 ns / 1 ns resolution check. These checks verify the specified implementation and temporal convergence. Experimental validation remains unresolved. Missing: PFC EOS/phase inventory, laser conversion, gel calibration and device geometry.

See the full worked derivation, native case register, numerical audit and the two native files in models/.

Models and rebuild

The 53-step guide builds both models from a blank 0D model. It provides inputs, solver settings, stopping rules and output checks. Markdown guide · Input files.

Model A — finite-energy outlet discharge
Model B — gel confinement and outlet transmission

Open the MPH files in COMSOL 6.4. Each includes one component, Global Equations and a transient study. Result tables and time histories are saved. These scalar models need no spatial mesh. Model B's outletOpen selects an existing channel or sealed control.

.\Run-Rebuild.ps1 rebuilds the native case family. .\Run-Verify.ps1 reloads and checks baselines. .\Run-CheckGuide.ps1 checks imports and A-to-B conversion in memory. Install requirements.txt for Python checks. Run python scripts/reference.py and python scripts/verify_results.py. Parameter changes and validity limits appear in README.md.

Editable LaTeX · Derivation source · Case inputs · Reader provenance

Complete worked derivation: 29 equation blocks with symbols, assumptions and checks

Two minimal single-event laser-cavitation models

Problem, architecture and scope

Model A calculates source pressure and first-ejection outlet speed. It uses specified source work, gas volume and liquid inventory. It also derives their energy ceilings. Model B adds hydrogel compliance and loss. It calculates gel load and the remaining emitted output.

An initially spherical chamber contains gas and carrier liquid. A liquid outlet already connects it to the surroundings. Initially connected chamber liquid sets the finite discharge budget. Effective channel inertance is a separate input. Model A fixes the chamber wall. Model B surrounds it with intact, undrained spherical hydrogel. Gas expansion enlarges the chamber or displaces liquid through the outlet. The sealed control fixes outlet motion at zero. This architecture describes expansion-driven external ejection. Collapse jets and gel penetration require different models.

A single 10 ns optical pulse is represented by post-activation initial data. Time zero follows activation and pressure equilibration. Optical heating, nucleation and energy conversion are excluded. There is no periodic load. Follow the first outward ejection until speed returns to zero. Stop sooner if liquid exhausts or a validity screen triggers. The sealed control stops at its first wall turning point. Evaluate speed maxima within these episodes. Later collapse and rebound are excluded.

Time starts at the initialized post-activation state. Positive outlet velocity points outward. Discharge coordinate means emitted volume divided by outlet area. Positive radial direction runs from chamber center into gel. Positive wall velocity means expansion. Ambient pressure is constant and absolute. Initially, the wall is stress-free relative to ambient. All initial mechanical velocities are zero. Chamber pressure is uniform. Gas-pocket shape and internal gas/liquid tension are neglected. The external meniscus supplies capillary resistance. Far-field radial stress tends to negative ambient pressure. Far-field displacement decays. The outlet exits at ambient with the specified meniscus pressure. An open case requires an existing channel. The sealed case emits zero liquid.

Constitutive assumptions. The source is a closed adiabatic ideal gas. Its exponent is constant. A PFC-vapor EOS is outside this control. Liquid and undrained gel densities are constant. The column has fixed effective inertance and a finite discharge budget. Gel elasticity is incompressible neo-Hookean with Kelvin–Voigt viscosity. Optional port losses are linear and quadratic. Outlet focusing, free-surface shape, fracture, phase exchange and diffusion remain unresolved. The spherical gel law approximates a chamber with a small outlet. Planar-layer mechanics requires a separate model. Material predictions require calibration.

Start from the first law, volume conservation and unsteady Bernoulli. Add the specified source EOS and spherical gel constitutive model. The course explains mechanisms and finite-energy budgets. Chapters 1–3 and Appendix A supply these model blocks. Brennen, Chapter 2 discusses spherical momentum and polytropic assumptions. The gas-volume coupling, finite-stroke rule and diagnostics are derived here.

Symbol glossary and conventions

All lengths use m, times s, masses kg, pressures Pa, energies J and forces N. Subscripts 0 and ref label initial and unstressed states; g, j, el, cap, dis and obs label gas, emitted jet, elastic, capillary, dissipative and observer quantities. Superscripts on scalar quantities are powers. A dot is a derivative in time. An integral is over the displayed real variable or surface. Absolute value is scalar magnitude. A hat labels the normalized state defined below. The constant pi is dimensionless. Arithmetic has its usual real meaning. No scalar is reused for a different role.

Symbol Meaning and restrictions Unit
tt Time after the initialized post-activation state s
x,Ux,U Discharged volume divided by outlet area, and outlet speed m, m/s
R,WR,W Chamber radius and wall velocity; W=R˙W=\dot R m, m/s
Rref,Rg0R_{\mathrm{ref}},R_{g0} Unstressed chamber radius and initial gas-pocket radius m
a,L,Lb,Aa,L,L_b,A Outlet radius, effective inertance length, discharge-budget length, and area m, m, m, m²
Vg,Vg0,Vc0,VeqV_g,V_{g0},V_{c0},V_{\mathrm{eq}} Current gas, initial gas, initial chamber, and ambient-equilibrium gas volumes m³
pb,p0,p∞p_b,p_0,p_\infty Current absolute source, initial absolute source, and absolute ambient pressures Pa
κ\kappa Constant adiabatic ideal-gas exponent, strictly greater than one dimensionless
Ug,E0\mathcal U_g,E_0 Gas internal energy and available adiabatic expansion work relative to ambient J
ρ,ρg,mc\rho,\rho_g,m_c Carrier density, undrained gel density, and effective liquid-column inertia mass kg/m³, kg/m³, kg
σ,pcap,Ecap\sigma,p_{\mathrm{cap}},E_{\mathrm{cap}} Effective surface tension, meniscus resistance, and reversible meniscus work N/m, Pa, J
R,Ko,ploss\mathcal R,K_o,p_{\mathrm{loss}} Fitted linear port resistance, dimensionless quadratic loss coefficient, dissipative port pressure Pa s/m, dimensionless, Pa
bob_o Outlet flag: one for an open channel, zero for sealed dimensionless
G,ηgG,\eta_g Positive gel shear modulus and nonnegative effective network viscosity Pa, Pa s
r,s,ξr,s,\xi Current gel radial coordinate, reference radial coordinate, dummy radius in a work integral m
λr,λt,β\lambda_r,\lambda_t,\beta Radial stretch, either equal tangential stretch, and change-of-variable ratio s/rs/r dimensionless
Trr,Ttt,χT_{rr},T_{tt},\chi Radial/tangential elastic Cauchy stress and incompressibility multiplier Pa
pel,presp_{\mathrm{el}},p_{\mathrm{res}} Elastic wall resistance and elastic-plus-viscous wall resistance Pa
Kc,Kg,Wg,D,EjK_c,K_g,W_g,D,E_j Column kinetic energy, gel kinetic energy, elastic work, irreversible losses, emitted energy J
Pport,PgelP_{\mathrm{port}},P_{\mathrm{gel}} Irreversible port and gel powers W
FhemF_{\mathrm{hem}} Axial resultant of elastic resistance on one chamber hemisphere N
θ,dΩ\theta,d\Omega Polar angle about the outlet axis and solid-angle element dimensionless
Us,τ,IsU_s,\tau,I_s Velocity, time and emitted-impulse normalization scales m/s, s, N s
x^,U^,R^,W^,D^,E^j,I^j\widehat x,\widehat U,\widehat R,\widehat W,\widehat D,\widehat E_j,\widehat I_j Seven normalized motion and accounting states dimensionless
εE\varepsilon_E Energy residual divided by available work dimensionless
Urms,qj,Ij,mjU_{\mathrm{rms}},q_j,I_j,m_j Emitted RMS speed, outlet dynamic-pressure scale, emitted impulse, emitted mass m/s, Pa, N s, kg
Aobs,τobs,pˉarrestA_{\mathrm{obs}},\tau_{\mathrm{obs}},\bar p_{\mathrm{arrest}} Declared observer area, averaging interval and mean arrest-pressure bound m², s, Pa
TU,TE,TI,TqT_U,T_E,T_I,T_q Matched peak-speed, emitted-energy, emitted-impulse and peak dynamic-pressure ratios dimensionless
cL,Lcomm,Cp,Mj,Mwc_L,L_{\mathrm{comm}},\mathcal C_p,M_j,M_w Reference communication speed, path length, communication ratio, liquid/wall Mach diagnostics m/s, m, dimensionless

| z,zi,zoz,z_i,z_o | Streamline coordinate and inlet/outlet positions | m | | u(z,t),f(z),A(z)u(z,t),f(z),\mathcal A(z) | Local speed, fixed area-ratio profile, and local cross-sectional area | m/s, dimensionless, m² | | F(Vg)\mathcal F(V_g) | Gas internal energy plus work against ambient, referred to initial volume | J |

Step 1 — Conserve volume and declare the finite source

Eq. (E01) — geometric identities.

Symbols before Eq. (E01): AA is outlet area (m²); aa is outlet radius (m); Vg0,Vc0,VgV_{g0},V_{c0},V_g are initial gas, initial chamber and current gas volumes (m³); Rg0,Rref,RR_{g0},R_{\mathrm{ref}},R are initial gas, reference chamber and current chamber radii (m); xx is discharged volume divided by area (m); LbL_b is discharge-budget length (m); pi is dimensionless.

A=πa2,Vg0=4πRg033,Vc0=4πRref33,Vg=Vg0+Ax+4π3(R3−Rref3),Lb=(Vc0−Vg0)/A.\begin{aligned} A&=\pi a^2,\qquad V_{g0}=\frac{4\pi R_{g0}^3}{3},\qquad V_{c0}=\frac{4\pi R_{\mathrm{ref}}^3}{3},\\ V_g&=V_{g0}+Ax+\frac{4\pi}{3}(R^3-R_{\mathrm{ref}}^3),\qquad L_b=(V_{c0}-V_{g0})/A. \end{aligned}

The second row conserves chamber liquid volume. Gas gains discharged liquid volume and chamber expansion volume. Model A fixes chamber expansion at zero. Stop when the finite liquid discharge budget is exhausted.

Eq. (E02) — initial data and admissible outward stroke.

Symbols before Eq. (E02): x,Rx,R are lengths (m); U,WU,W are liquid and wall speeds (m/s); Rref,LbR_{\mathrm{ref}},L_b are positive reference radius and discharge-budget length (m); AA is area (m²); Vc0,Vg0V_{c0},V_{g0} are initial volumes (m³); argument zero labels initialization.

x(0)=0,U(0)=0,R(0)=Rref,W(0)=0,0≤x≤Lb,Ax<Vc0−Vg0.x(0)=0,\quad U(0)=0,\quad R(0)=R_{\mathrm{ref}},\quad W(0)=0, \qquad 0\le x\le L_b,\qquad Ax<V_{c0}-V_{g0}.

Zero initial speeds are specified post-activation inputs. Nucleation is excluded. The finite stroke bounds discharged mass.

Eq. (E03) — adopted ideal-gas energy and adiabatic first law.

Symbols before Eq. (E03): Ug\mathcal U_g is internal energy (J); pbp_b is absolute source pressure (Pa); VgV_g is gas volume (m³); κ>1\kappa>1 is the constant ideal-gas exponent; dd denotes a differential along the closed adiabatic source trajectory.

Ug=pbVgκ−1,dUg=−pb dVg,Vg dpb+pb dVg=−(κ−1)pb dVg.\mathcal U_g=\frac{p_bV_g}{\kappa-1},\qquad d\mathcal U_g=-p_b\,dV_g,\qquad V_g\,dp_b+p_b\,dV_g=-(\kappa-1)p_b\,dV_g.

The first relation defines the source constitutive model. The second applies its adiabatic first-law balance. Heat and mass exchange vanish after initialization. Differentiate the first relation. Multiply by the exponent minus one to obtain the third. Condensation and further PFC vapor production are excluded.

Eq. (E04) — integrate the pressure law.

Symbols before Eq. (E04): pb,p0p_b,p_0 are positive current and initial absolute pressures (Pa); Vg,Vg0V_g,V_{g0} are positive current and initial volumes (m³); κ>1\kappa>1 is dimensionless; ln⁡\ln is the logarithm of a dimensionless ratio; dd is a trajectory differential.

Vg dpb=−κpb dVg,dpbpb=−κdVgVg,ln⁡pbp0=−κln⁡VgVg0,pb=p0(Vg0Vg)κ.\begin{aligned} V_g\,dp_b&=-\kappa p_b\,dV_g,\\ \frac{dp_b}{p_b}&=-\kappa\frac{dV_g}{V_g},\\ \ln\frac{p_b}{p_0}&=-\kappa\ln\frac{V_g}{V_{g0}},\\ p_b&=p_0\left(\frac{V_{g0}}{V_g}\right)^\kappa. \end{aligned}

Collect the differential terms in Eq. (E03). Divide by positive pressure and volume. Integrate from the initial state to fix the constant. Exponentiation gives the pressure law. Expansion lowers pressure. No periodic source is prescribed.

Step 2 — Compute the finite work budget

Eq. (E05) — ambient equilibrium and available expansion work.

Symbols before Eq. (E05): Veq,Vg0V_{\mathrm{eq}},V_{g0} are gas volumes (m³); p0>p∞>0p_0>p_\infty>0 are initial source and ambient absolute pressures (Pa); κ>1\kappa>1 is dimensionless; E0E_0 is available adiabatic expansion work (J); vv is a dummy positive gas volume (m³); the integral is along the declared pressure-volume path.

p∞=p0(Vg0/Veq)κ⟹Veq=Vg0(p0/p∞)1/κ,E0=∫Vg0Veq[p0(Vg0v)κ−p∞]dv=p0Vg0κ[v1−κ1−κ]Vg0Veq−p∞(Veq−Vg0)=p0Vg0κ−1[1−(Vg0Veq)κ−1]−p∞(Veq−Vg0).\begin{aligned} p_\infty&=p_0(V_{g0}/V_{\mathrm{eq}})^\kappa \quad\Longrightarrow\quad V_{\mathrm{eq}}=V_{g0}(p_0/p_\infty)^{1/\kappa},\\ E_0&=\int_{V_{g0}}^{V_{\mathrm{eq}}} \left[p_0\left(\frac{V_{g0}}v\right)^\kappa-p_\infty\right]dv\\ &=p_0V_{g0}^\kappa\left[\frac{v^{1-\kappa}}{1-\kappa}\right]_{V_{g0}}^{V_{\mathrm{eq}}} -p_\infty(V_{\mathrm{eq}}-V_{g0})\\ &=\frac{p_0V_{g0}}{\kappa-1} \left[1-\left(\frac{V_{g0}}{V_{\mathrm{eq}}}\right)^{\kappa-1}\right] -p_\infty(V_{\mathrm{eq}}-V_{g0}). \end{aligned}

Apply Eq. (E04) at ambient pressure. Take the positive root to find equilibrium volume. Integrate overpressure to define available work. Integrate the volume power, whose exponent differs from one. Evaluate both endpoints and factor the initial volume. Pressure times volume has units J. Numerically invert this monotone relation for initial pressure. Changing the work budget changes the initial state. It adds no later work.

Available work means post-activation mechanical availability. Incident optical energy is a separate quantity. Determine available work from a measured pressure-volume path. Alternatively, use absorbed energy with a supported conversion and phase model. Source mass and phase composition must support the initialized state. Conversion efficiency and PFC EOS remain unspecified.

Eq. (E05a) — uniqueness of the finite-work inversion.

Symbols before Eq. (E05a): E0E_0 is available work (J); p0>p∞p_0>p_\infty are initial and ambient pressures (Pa); Vg0,Veq,vV_{g0},V_{\mathrm{eq}},v are initial, equilibrium and dummy gas volumes (m³); κ>1\kappa>1 is dimensionless; ∂/∂p0\partial/\partial p_0 fixes initial volume, ambient pressure and exponent; lim⁡\lim denotes the indicated pressure limit.

∂E0∂p0=∫Vg0Veq(Vg0/v)κdv+[p0(Vg0/Veq)κ−p∞]∂Veq∂p0=Vg0κ−1[1−(Vg0/Veq)κ−1]>0,E0∣p0=p∞=0,lim⁡p0→∞E0p0=Vg0κ−1.\begin{aligned} \frac{\partial E_0}{\partial p_0} &=\int_{V_{g0}}^{V_{\mathrm{eq}}}(V_{g0}/v)^\kappa dv +[p_0(V_{g0}/V_{\mathrm{eq}})^\kappa-p_\infty]\frac{\partial V_{\mathrm{eq}}}{\partial p_0}\\ &=\frac{V_{g0}}{\kappa-1}[1-(V_{g0}/V_{\mathrm{eq}})^{\kappa-1}]>0,\\ E_0\big|_{p_0=p_\infty}&=0,\qquad \lim_{p_0\to\infty}\frac{E_0}{p_0}=\frac{V_{g0}}{\kappa-1}. \end{aligned}

Apply Leibniz differentiation in the first row. The endpoint pressure equals ambient, so its term vanishes. Integrate the remaining positive power for the second row. Equal source and ambient pressures give zero work. Equilibrium-volume terms grow sublinearly at large source pressure. This gives the final limit. Positive available work therefore selects a unique initial pressure.

Step 3 — Accelerate an outlet flow and retain actual emitted output

Eq. (E06) — inertia, capillary resistance and port loss.

Symbols before Eq. (E06): mcm_c is effective column inertia mass (kg); ρ\rho is carrier density (kg/m³); AA is outlet area (m²); L,aL,a are inertance length and outlet radius (m); pcap,plossp_{\mathrm{cap}},p_{\mathrm{loss}} are pressures (Pa); σ\sigma is tension (N/m); R≥0\mathcal R\ge0 is fitted resistance (Pa s/m); Ko≥0K_o\ge0 is dimensionless; UU is outlet speed (m/s); absolute value denotes magnitude.

mc=ρAL,pcap=2σ/a,ploss=RU+ρKoU∣U∣/2.m_c=\rho AL,\qquad p_{\mathrm{cap}}=2\sigma/a,\qquad p_{\mathrm{loss}}=\mathcal R U+\rho K_oU|U|/2.

Column inertia and emitted mass are separate quantities. The meniscus model assumes a pinned hemisphere. Different curvature requires different entry pressure. Measure or fit the linear resistance. Steady Poiseuille resistance needs justification for this short event. The odd-in-speed loss dissipates energy in either direction.

Meniscus pressure stays constant during this episode. Its integral is work against a constant conservative load. The model excludes evolving free-surface energy. Persistent hemispherical curvature during jet formation is not established. Changing curvature, contact-line motion or breakup requires a revised entry model.

Eq. (E06a) — derive inertance and the outgoing kinetic head.

Symbols before Eq. (E06a): z,zi,zoz,z_i,z_o are streamline coordinate and inlet/outlet positions (m); u(z,t)u(z,t) is local speed and U(t)U(t) outlet speed (m/s); f(z)f(z) is a fixed dimensionless profile; A,A(z)A,\mathcal A(z) are outlet and local areas (m²); LL is inertance length (m); ρ\rho is density (kg/m³); p(z,t)p(z,t) is pressure (Pa); tt is time (s); ∂t,∂z\partial_t,\partial_z are fixed-position derivatives; a dot is a time derivative. The large-reservoir approximation sets inlet speed to zero and outlet profile to one.

u(z,t)=f(z)U(t),f(z)=A/A(z),L=∫zizof(z)dz,ρ(∂tu+u∂zu)=−∂zp,∫zizo(∂tu+u∂zu)dz=LU˙+[u2/2]zizo=LU˙+U2/2,12ρ∫zizoA(z)u2dz=12ρAU2∫zizof(z)dz=12ρALU2.\begin{aligned} u(z,t)&=f(z)U(t),\quad f(z)=A/\mathcal A(z),\quad L=\int_{z_i}^{z_o}f(z)dz,\\ \rho(\partial_tu+u\partial_zu)&=-\partial_zp,\\ \int_{z_i}^{z_o}(\partial_tu+u\partial_zu)dz &=L\dot U+[u^2/2]_{z_i}^{z_o}=L\dot U+U^2/2,\\ \frac12\rho\int_{z_i}^{z_o}\mathcal A(z)u^2dz &=\frac12\rho AU^2\int_{z_i}^{z_o}f(z)dz=\frac12\rho ALU^2. \end{aligned}

Fixed-geometry continuity gives the first velocity profile. The second row applies inviscid streamline Euler momentum. Integrate the fixed profile to obtain inertance. Integrate convection to obtain endpoint kinetic heads. Neglect reservoir inlet speed and retain outlet head. Substitute the continuity area relation in the energy integral. This yields the same inertance length. The approximation represents an existing channel. Free-surface focusing and transverse kinetic energy are excluded. Calibrate effective inertance and loss for the actual geometry.

Eq. (E07) — unsteady Bernoulli and the explicit outlet flag.

Symbols before Eq. (E07): xx is discharged volume divided by outlet area (m); UU is outward outlet speed (m/s); dots are time derivatives; bob_o is the open/sealed flag; ρ\rho is density (kg/m³); LL is inertance length (m); pb,p∞,pcap,plossp_b,p_\infty,p_{\mathrm{cap}},p_{\mathrm{loss}} are source, ambient, meniscus and dissipative pressures (Pa).

pb−p∞−pcap−ploss=ρLU˙+ρU2/2(bo=1),x˙=boU,U˙=boρL(pb−p∞−pcap−ploss−ρU2/2).\begin{aligned} p_b-p_\infty-p_{\mathrm{cap}}-p_{\mathrm{loss}}&=\rho L\dot U+\rho U^2/2\quad(b_o=1),\\ \dot x&=b_oU,\qquad \dot U=\frac{b_o}{\rho L}(p_b-p_\infty-p_{\mathrm{cap}}-p_{\mathrm{loss}}-\rho U^2/2). \end{aligned}

Integrate the pressure gradient in Eq. (E06a). Add the specified meniscus and dissipative pressure drops. Divide by positive density and inertance length. This gives outlet acceleration. A sealed outlet retains its zero initial speed. The kinetic-head term accounts for energy leaving the outlet.

Eq. (E08) — column storage and dissipative power.

Symbols before Eq. (E08): Kc,EcapK_c,E_{\mathrm{cap}} are stored energies (J); mcm_c is effective inertia mass (kg); UU is outlet speed (m/s); pcap,pb,p∞p_{\mathrm{cap}},p_b,p_\infty are pressures (Pa); AA is area (m²); xx is discharge volume divided by area (m); PportP_{\mathrm{port}} is dissipative power (W); R\mathcal R is resistance (Pa s/m); ρ\rho is density (kg/m³); Ko,boK_o,b_o are dimensionless; d/dtd/dt is a time derivative.

Kc=mcU2/2,Ecap=pcapAx,Pport=boA(RU2+ρKo∣U∣3/2)≥0,ddt(Kc+Ecap)=boA(pb−p∞)U−Pport−boρAU3/2.\begin{aligned} K_c&=m_cU^2/2,\qquad E_{\mathrm{cap}}=p_{\mathrm{cap}}Ax,\\ P_{\mathrm{port}}&=b_oA(\mathcal R U^2+\rho K_o|U|^3/2)\ge0,\\ \frac{d}{dt}(K_c+E_{\mathrm{cap}})&=b_oA(p_b-p_\infty)U-P_{\mathrm{port}}-b_o\rho AU^3/2. \end{aligned}

Differentiate stored energy and insert Eq. (E07). Add meniscus work to cancel the meniscus pressure term. Dissipative pressure times flow rate gives dissipative power. The final kinetic-head term gives emitted power. Column storage and irreversible loss remain separate.

Eq. (E08a) — finite emitted mass, energy and impulse.

Symbols before Eq. (E08a): mjm_j is emitted mass (kg); EjE_j is discharged kinetic energy (J); IjI_j is discharged axial impulse (N s); ρ\rho is density (kg/m³); AA is area (m²); xx is discharge volume divided by area (m); UU is nonnegative outlet speed (m/s); bob_o is the outlet flag; dots are time derivatives and argument zero labels initialization.

mj=ρAx,E˙j=boρAU3/2,I˙j=boρAU2,Ej(0)=Ij(0)=0.m_j=\rho Ax,\quad \dot E_j=b_o\rho AU^3/2,\quad \dot I_j=b_o\rho AU^2,\quad E_j(0)=I_j(0)=0.

Multiply mass flow by specific kinetic energy for emitted power. Multiply it by axial speed for emitted impulse rate. Integrate each rate over time. Column energy and momentum describe instantaneous storage. Emitted energy and impulse describe discharged output.

Step 4 — Retain only the gel mechanics needed for confinement

Eq. (E09) — incompressible spherical mapping and principal stretches.

Symbols before Eq. (E09): r,s,R,Rrefr,s,R,R_{\mathrm{ref}} are current material radius, reference material radius, current wall radius and reference wall radius (m); λr,λt\lambda_r,\lambda_t are dimensionless radial and tangential stretches; ∂r/∂s\partial r/\partial s differentiates at fixed time; r≥R>0r\ge R>0 and s≥Rref>0s\ge R_{\mathrm{ref}}>0.

r3−R3=s3−Rref3,3r2∂r∂s=3s2,λr=s2r2,λt=rs,λrλt2=1.\begin{aligned} r^3-R^3&=s^3-R_{\mathrm{ref}}^3,\\ 3r^2\frac{\partial r}{\partial s}&=3s^2,\\ \lambda_r&=\frac{s^2}{r^2},\qquad\lambda_t=\frac rs,\qquad \lambda_r\lambda_t^2=1. \end{aligned}

Equate reference and current material volumes outside the wall. Differentiate that mapping for the second row. Use radial and tangential length ratios for the third. Their product checks local volume conservation.

Eq. (E10) — declared neo-Hookean stress and radial equilibrium.

Symbols before Eq. (E10): Trr,Ttt,χT_{rr},T_{tt},\chi are radial/tangential Cauchy stress and an incompressibility multiplier (Pa); GG is shear modulus (Pa); λr,λt\lambda_r,\lambda_t are stretches; r,sr,s are material radii (m); dTrr/drdT_{rr}/dr is a radial derivative (Pa/m).

Trr=−χ+Gλr2,Ttt=−χ+Gλt2,Ttt−Trr=G[(r/s)2−(s/r)4],dTrrdr=2r(Ttt−Trr).\begin{aligned} T_{rr}&=-\chi+G\lambda_r^2,\qquad T_{tt}=-\chi+G\lambda_t^2,\\ T_{tt}-T_{rr}&=G[(r/s)^2-(s/r)^4],\\ \frac{dT_{rr}}{dr}&=\frac2r(T_{tt}-T_{rr}). \end{aligned}

The first row is the adopted constitutive law. Subtract the stresses to eliminate constraint pressure. The third row states spherical elastic equilibrium. Its integral gives elastic resistance. Radial inertia and viscosity are added separately below.

Eq. (E11) — evaluate the spherical elastic resistance.

Symbols before Eq. (E11): pelp_{\mathrm{el}} is elastic resistance pressure (Pa); GG is shear modulus (Pa); R,Rref,r,sR,R_{\mathrm{ref}},r,s are radii (m); β=s/r\beta=s/r is a positive dimensionless integration variable; dd denotes a differential; the radial integral uses the infinite-medium stress boundary condition.

pel=2G∫R∞[(r/s)2−(s/r)4]drr,β3=1−R3−Rref3r3,drr=β2 dβ1−β3,[(r/s)2−(s/r)4]drr=1−β61−β3 dβ=(1+β3)dβ,pel=2G∫Rref/R1(1+β3)dβ=2G[β+β4/4]Rref/R1=G2[5−4RrefR−(RrefR)4].\begin{aligned} p_{\mathrm{el}}&=2G\int_R^\infty[(r/s)^2-(s/r)^4]\frac{dr}{r},\\ \beta^3&=1-\frac{R^3-R_{\mathrm{ref}}^3}{r^3},\quad \frac{dr}{r}=\frac{\beta^2\,d\beta}{1-\beta^3},\\ [(r/s)^2-(s/r)^4]\frac{dr}{r} &=\frac{1-\beta^6}{1-\beta^3}\,d\beta=(1+\beta^3)d\beta,\\ p_{\mathrm{el}}&=2G\int_{R_{\mathrm{ref}}/R}^{1}(1+\beta^3)d\beta =2G[\beta+\beta^4/4]_{R_{\mathrm{ref}}/R}^{1}\\ &=\frac G2\left[5-4\frac{R_{\mathrm{ref}}}{R}-\left(\frac{R_{\mathrm{ref}}}{R}\right)^4\right]. \end{aligned}

Integrate the stress difference in Eq. (E10). Differentiate the volume mapping at fixed wall radius. Substitute it to obtain the third row. Factor the difference of squares and cancel the common factor. The wall endpoint is reference radius divided by current radius. The far-field endpoint is one. Integrate the polynomial and evaluate both endpoints. The last two rows recover Appendix A, Eq. (A-E05). No wave field is required.

Eq. (E12) — integrate the recoverable gel work.

Symbols before Eq. (E12): WgW_g is elastic work (J); GG is shear modulus (Pa); R,Rref,ξR,R_{\mathrm{ref}},\xi are current wall, reference wall and dummy wall radii (m); pel(ξ)p_{\mathrm{el}}(\xi) is the pressure from Eq. (E11) evaluated at the dummy radius (Pa); pi is dimensionless.

Wg=4π∫RrefRpel(ξ)ξ2dξ=2πG∫RrefR(5ξ2−4Rrefξ−Rref4ξ−2)dξ=2πG[5ξ33−2Rrefξ2+Rref4ξ]RrefR=2πG[5R33−2RrefR2+Rref4R−2Rref33].\begin{aligned} W_g&=4\pi\int_{R_{\mathrm{ref}}}^{R}p_{\mathrm{el}}(\xi)\xi^2d\xi\\ &=2\pi G\int_{R_{\mathrm{ref}}}^{R} (5\xi^2-4R_{\mathrm{ref}}\xi-R_{\mathrm{ref}}^4\xi^{-2})d\xi\\ &=2\pi G\left[\frac{5\xi^3}{3}-2R_{\mathrm{ref}}\xi^2+\frac{R_{\mathrm{ref}}^4}{\xi}\right]_{R_{\mathrm{ref}}}^{R}\\ &=2\pi G\left[\frac{5R^3}{3}-2R_{\mathrm{ref}}R^2+\frac{R_{\mathrm{ref}}^4}{R}-\frac{2R_{\mathrm{ref}}^3}{3}\right]. \end{aligned}

The first row integrates traction against spherical volume change. Insert Eq. (E11) and integrate each power. Evaluate both endpoints. The lower endpoint is two-thirds of the reference-radius cube. Modulus times volume gives J. This energy is recoverable elastic storage.

Eq. (E13) — gel resistance checks.

Symbols before Eq. (E13): pelp_{\mathrm{el}} is pressure (Pa); WgW_g is energy (J); GG is modulus (Pa); R,Rref,δRR,R_{\mathrm{ref}},\delta R are lengths (m); d/dRd/dR is radius differentiation; OO denotes terms of the indicated small-displacement order; lim⁡\lim is the stated radius limit.

pel(Rref)=0,Wg(Rref)=0,dpeldR=2G(RrefR2+Rref4R5)>0,dWgdR=4πR2pel,pel(Rref+δR)=4GδRRref+O(GδR2/Rref2),Wg(Rref+δR)=8πGRrefδR2+O(GδR3),lim⁡R/Rref→∞pel=52G.\begin{aligned} p_{\mathrm{el}}(R_{\mathrm{ref}})&=0,\qquad W_g(R_{\mathrm{ref}})=0,\\ \frac{dp_{\mathrm{el}}}{dR}&=2G\left(\frac{R_{\mathrm{ref}}}{R^2}+\frac{R_{\mathrm{ref}}^4}{R^5}\right)>0,\qquad \frac{dW_g}{dR}=4\pi R^2p_{\mathrm{el}},\\ p_{\mathrm{el}}(R_{\mathrm{ref}}+\delta R)&=4G\frac{\delta R}{R_{\mathrm{ref}}}+O(G\delta R^2/R_{\mathrm{ref}}^2),\\ W_g(R_{\mathrm{ref}}+\delta R)&=8\pi G R_{\mathrm{ref}}\delta R^2+O(G\delta R^3),\qquad \lim_{R/R_{\mathrm{ref}}\to\infty}p_{\mathrm{el}}=\frac52G. \end{aligned}

Substitute the unstressed radius to check the reference state. Differentiate work to check traction. Taylor expansion gives positive small-strain stiffness and quadratic stored work. Infinite radius ratio gives a pressure plateau. Work still grows with volume. Damage tolerance and useful jet formation are not established.

Step 5 — Add radial inertia and viscous loss

Eq. (E14) — spherical radial kinetic energy and Newtonian gel loss.

Symbols before Eq. (E14): KgK_g is radial gel kinetic energy (J); ρg\rho_g is density (kg/m³); R,WR,W are wall radius and speed (m, m/s); rr is spatial radius (m); ηg\eta_g is network viscosity (Pa s); PgelP_{\mathrm{gel}} is irreversible power (W); pres,pelp_{\mathrm{res}},p_{\mathrm{el}} are wall resistance pressures (Pa); pi is dimensionless.

Kg=∫R∞12ρg(R2Wr2)24πr2dr=2πρgR4W2[−1r]R∞=2πρgR3W2,pres=pel+4ηgWR,Pgel=16πηgRW2≥0.\begin{aligned} K_g&=\int_R^\infty\frac12\rho_g\left(\frac{R^2W}{r^2}\right)^2 4\pi r^2dr =2\pi\rho_gR^4W^2\left[-\frac1r\right]_R^\infty =2\pi\rho_gR^3W^2,\\ p_{\mathrm{res}}&=p_{\mathrm{el}}+\frac{4\eta_gW}{R},\qquad P_{\mathrm{gel}}=16\pi\eta_gRW^2\ge0. \end{aligned}

The volume mapping gives radial velocity. Squaring it produces a convergent reciprocal-square radial integral. Use the appendix Kelvin–Voigt coefficients, Eqs. (A-E09)–(A-E12). Viscosity opposes both directions of wall motion. Its dissipated power is nonnegative. Radiation and wave-field losses are excluded.

Eq. (E15) — radial motion and its energy identity.

Symbols before Eq. (E15): R,WR,W are wall radius and speed (m, m/s); dots are time derivatives; ρg\rho_g is density (kg/m³); pb,p∞,pelp_b,p_\infty,p_{\mathrm{el}} are pressures (Pa); ηg\eta_g is viscosity (Pa s); Kg,WgK_g,W_g are energies (J); PgelP_{\mathrm{gel}} is power (W); pi is dimensionless.

R˙=W,ρg(RW˙+32W2)=pb−p∞−pel−4ηgWR,dKgdt=2πρg(3R2W3+2R3WW˙)=4πR2W ρg(RW˙+32W2),ddt(Kg+Wg)=4πR2W(pb−p∞)−Pgel.\begin{aligned} \dot R&=W,\qquad \rho_g\left(R\dot W+\frac32W^2\right)=p_b-p_\infty-p_{\mathrm{el}}-\frac{4\eta_gW}{R},\\ \frac{dK_g}{dt}&=2\pi\rho_g(3R^2W^3+2R^3W\dot W) =4\pi R^2W\,\rho_g\left(R\dot W+\frac32W^2\right),\\ \frac{d}{dt}(K_g+W_g)&=4\pi R^2W(p_b-p_\infty)-P_{\mathrm{gel}}. \end{aligned}

The first row adopts undrained spherical momentum balance. Initial elastic overpressure is zero. Differentiate kinetic energy in Eq. (E14) using the product rule. Substitute wall kinematics to obtain the second row. Multiply the first row by volume rate. Insert elastic work from Eq. (E13). Insert viscous power from Eq. (E14) for the third row. Model A fixes radius, eliminating radial kinetic and elastic storage.

Eq. (E16) — a defined confinement force.

Symbols before Eq. (E16): FhemF_{\mathrm{hem}} is axial force on one hemisphere (N); pelp_{\mathrm{el}} is uniform spherical elastic resistance (Pa); RR is radius (m); θ\theta is polar angle measured from the outlet axis; pi is dimensionless; the integral projects traction onto that axis.

Fhem=∫0π/2pelcos⁡θ 2πR2sin⁡θ dθ=2πR2pel[sin⁡2θ2]0π/2=πR2pel.F_{\mathrm{hem}}=\int_0^{\pi/2}p_{\mathrm{el}}\cos\theta\,2\pi R^2\sin\theta\,d\theta =2\pi R^2p_{\mathrm{el}}\left[\frac{\sin^2\theta}{2}\right]_0^{\pi/2} =\pi R^2p_{\mathrm{el}}.

This force is the directional resultant on one hemisphere. The complete sphere has zero resultant by symmetry. Integrating pressure magnitude over a sphere gives a different quantity. A target patch requires its own area and load path.

Step 6 — Close and audit the combined energy balance

Eq. (E17) — total source volume rate and accumulated loss.

Symbols before Eq. (E17): VgV_g is gas volume (m³); AA is area (m²); U,WU,W are speeds (m/s); RR is radius (m); bob_o is the open/sealed flag; DD is accumulated loss (J); Pport,PgelP_{\mathrm{port}},P_{\mathrm{gel}} are powers (W); dots denote time derivatives.

V˙g=boAU+4πR2W,D˙=Pport+Pgel,D(0)=0.\dot V_g=b_oAU+4\pi R^2W,\qquad \dot D=P_{\mathrm{port}}+P_{\mathrm{gel}},\qquad D(0)=0.

Differentiate Eq. (E01) and insert both kinematic relations. Add port and gel dissipation from their separate motions.

Eq. (E18) — explicit cancellation of source-to-receiver work.

Symbols before Eq. (E18): Ug,Kc,Kg,Wg,Ecap,D,Ej\mathcal U_g,K_c,K_g,W_g,E_{\mathrm{cap}},D,E_j are stored, lost and emitted energies (J); pb,p∞p_b,p_\infty are pressures (Pa); VgV_g is gas volume (m³); AA is area (m²); U,WU,W are speeds (m/s); RR is radius (m); bob_o is dimensionless; d/dtd/dt is a time derivative; pi is dimensionless.

ddt(Ug+p∞Vg+Kc+Kg+Wg+Ecap+D+Ej)=(−pb+p∞)V˙g+(pb−p∞)(boAU+4πR2W)=0.\begin{aligned} \frac{d}{dt}(\mathcal U_g+p_\infty V_g+K_c+K_g+W_g+E_{\mathrm{cap}}+D+E_j) &=(-p_b+p_\infty)\dot V_g+(p_b-p_\infty)(b_oAU+4\pi R^2W)\\ &=0. \end{aligned}

Combine the source first law, Eq. (E03), with column storage, Eq. (E08). Add radial storage, Eq. (E15), and accumulated loss, Eq. (E17). Each dissipative power cancels its loss accumulator. Emitted kinetic power cancels Eq. (E08a). Substitute volume rate to cancel the remaining source exchange. One evolving source pressure closes this balance. An independently prescribed radius history would break it.

Eq. (E19) — numerical acceptance residual.

Symbols before Eq. (E19): εE\varepsilon_E is dimensionless residual; pb,p0,p∞p_b,p_0,p_\infty are pressures (Pa); Vg,Vg0V_g,V_{g0} are volumes (m³); κ>1\kappa>1 is dimensionless; Kc,Kg,Wg,Ecap,D,Ej,E0K_c,K_g,W_g,E_{\mathrm{cap}},D,E_j,E_0 are stored, lost, emitted and available energies (J), with strictly positive available work.

εE=pbVg/(κ−1)−p0Vg0/(κ−1)+p∞(Vg−Vg0)+Kc+Kg+Wg+Ecap+D+EjE0.\varepsilon_E= \frac{p_bV_g/(\kappa-1)-p_0V_{g0}/(\kappa-1)+p_\infty(V_g-V_{g0})+K_c+K_g+W_g+E_{\mathrm{cap}}+D+E_j}{E_0}.

Subtract initial stored energy from Eq. (E18), then normalize. Include gel kinetic and elastic storage. A near-zero residual checks numerical conservation. EOS and geometry calibration require separate evidence.

Step 7 — Map the equations to native COMSOL states

Eq. (E20) — normalization definitions.

Symbols before Eq. (E20): UsU_s is speed scale (m/s); τ\tau is time scale (s); IsI_s is impulse scale (N s); Rref,Lb,R,xR_{\mathrm{ref}},L_b,R,x are lengths (m); U,WU,W are speeds (m/s); mcm_c is effective column mass (kg); D,Ej,E0D,E_j,E_0 are losses, emitted energy and available work (J); IjI_j is emitted impulse (N s); seven hatted states are dimensionless normalized quantities.

τ=Rref/Us,Is=mcUs,x^=x/Lb,U^=U/Us,R^=R/Rref,W^=W/Us,D^=D/E0,E^j=Ej/E0,I^j=Ij/Is.\begin{aligned} \tau&=R_{\mathrm{ref}}/U_s,\qquad I_s=m_cU_s,\\ \widehat x&=x/L_b,\quad\widehat U=U/U_s,\quad\widehat R=R/R_{\mathrm{ref}},\quad\widehat W=W/U_s,\\ \widehat D&=D/E_0,\qquad\widehat E_j=E_j/E_0,\qquad\widehat I_j=I_j/I_s. \end{aligned}

Normalization changes scales without changing the model. Native states are qq, vv, rr, ww, dd, ee, ii. Model A excludes two radial states, leaving five scalars. Model B uses seven. Three accumulate loss, emitted energy and emitted impulse.

Eq. (E21) — dimensionless residuals integrated in physical time.

Symbols before Eq. (E21): all hatted states are dimensionless; their dots differentiate in physical time (1/s); τ\tau is time (s); bob_o is the outlet flag; U,W,UsU,W,U_s are speeds (m/s); L,Lb,R,RrefL,L_b,R,R_{\mathrm{ref}} are lengths (m); ρ,ρg\rho,\rho_g are densities (kg/m³); pb,p∞,pcap,ploss,pelp_b,p_\infty,p_{\mathrm{cap}},p_{\mathrm{loss}},p_{\mathrm{el}} are pressures (Pa); ηg\eta_g is viscosity (Pa s); Pport,PgelP_{\mathrm{port}},P_{\mathrm{gel}} are powers (W); E0E_0 is work (J); AA is area (m²); IsI_s is impulse scale (N s).

0=τ(x^˙−boU/Lb),0=τ[U^˙−bo(pb−p∞−pcap−ploss−ρU2/2)ρLUs],0=τ(R^˙−W/Rref),0=τ[W^˙−(pb−p∞−pel−4ηgW/R)/ρg−3W2/2RUs],0=τ[D^˙−(Pport+Pgel)/E0],0=τ(E^j˙−boρAU3/(2E0)),0=τ(I^j˙−boρAU2/Is).\begin{aligned} 0&=\tau(\dot{\widehat x}-b_oU/L_b),\\ 0&=\tau\left[\dot{\widehat U}-\frac{b_o(p_b-p_\infty-p_{\mathrm{cap}}-p_{\mathrm{loss}}-\rho U^2/2)}{\rho LU_s}\right],\\ 0&=\tau(\dot{\widehat R}-W/R_{\mathrm{ref}}),\\ 0&=\tau\left[\dot{\widehat W}-\frac{(p_b-p_\infty-p_{\mathrm{el}}-4\eta_gW/R)/\rho_g-3W^2/2}{RU_s}\right],\\ 0&=\tau[\dot{\widehat D}-(P_{\mathrm{port}}+P_{\mathrm{gel}})/E_0],\\ 0&=\tau(\dot{\widehat E_j}-b_o\rho AU^3/(2E_0)),\\ 0&=\tau(\dot{\widehat I_j}-b_o\rho AU^2/I_s). \end{aligned}

Insert Eq. (E20) into motion and accounting equations. Divide speed derivatives and accumulated quantities by their respective scales. Multiply each row by the time scale. Every residual is dimensionless. Model A fixes the wall and excludes radial rows. Total gas volume determines algebraic source pressure.

Step 8 — Bound defined velocities, emitted output and pressure observers

Eq. (E22a) — show the minimum of source mechanical potential.

Symbols before Eq. (E22a): F\mathcal F is source internal energy plus work against ambient, referenced to initial volume (J); Ug\mathcal U_g is internal energy (J); p∞,pbp_\infty,p_b are positive pressures (Pa); Vg,Vg0,VeqV_g,V_{g0},V_{\mathrm{eq}} are volumes (m³); κ>1\kappa>1 is dimensionless; E0E_0 is available work (J); derivatives are with respect to positive gas volume.

F(Vg)=Ug(Vg)+p∞(Vg−Vg0),F′(Vg)=p∞−pb,F′′(Vg)=κpb/Vg>0,F(Vg0)−F(Veq)=E0.\mathcal F(V_g)=\mathcal U_g(V_g)+p_\infty(V_g-V_{g0}),\quad \mathcal F'(V_g)=p_\infty-p_b,\quad \mathcal F''(V_g)=\kappa p_b/V_g>0,\quad \mathcal F(V_{g0})-\mathcal F(V_{\mathrm{eq}})=E_0.

The source first law gives the first derivative. Differentiate Eq. (E04) for the second. Strict convexity gives a unique global minimum at ambient pressure. Evaluate the potential difference to obtain Eq. (E05). This establishes the work budget within the adopted control.

Eq. (E22) — separate outlet-speed and emitted-RMS ceilings.

Symbols before Eq. (E22): Kc,Ej,E0K_c,E_j,E_0 are column kinetic energy, emitted energy and available work (J); mc>0m_c>0 is effective column inertia mass (kg); mj>0m_j>0 is actual emitted mass (kg); UU is outlet speed (m/s); UrmsU_{\mathrm{rms}} is emitted mass-weighted RMS speed (m/s); qjq_j is outlet dynamic-pressure scale (Pa); ρ\rho is density (kg/m³); A,LA,L are outlet area and inertance length (m², m); square roots are nonnegative.

Kc+Ej≤E0,∣U∣≤2E0/mc,Urms=2Ej/mj≤2E0/mj,qj=ρU2/2≤E0/(AL).\begin{aligned} K_c+E_j&\le E_0,\qquad |U|\le\sqrt{2E_0/m_c},\\ U_{\mathrm{rms}}&=\sqrt{2E_j/m_j}\le\sqrt{2E_0/m_j},\\ q_j&=\rho U^2/2\le E_0/(AL). \end{aligned}

Every listed receiver energy is nonnegative on the outward branch. Combine Eq. (E18) with the minimum in Eq. (E22a). Isolate column kinetic energy and divide by positive effective mass. This gives the outlet-speed ceiling. Emitted energy and positive emitted mass define the RMS ceiling. Insert column mass from Eq. (E06) for the dynamic-pressure ceiling. The outlet ceiling depends on effective inertance. The emitted-RMS ceiling follows from conservation and specified mass. Liquid exhaustion may stop the trajectory before either ceiling.

A finite energy budget needs a positive mass lower bound. Without it, a universal RMS-speed maximum cannot be computed. A pointwise pressure maximum needs a contact or compression model. Missing: area, duration and load path. Source pressure, outlet dynamic pressure and observer pressure are distinct quantities.

Eq. (E23) — finite emitted impulse and a mean arrest-pressure bound.

Symbols before Eq. (E23): IjI_j is emitted impulse (N s); mjm_j is emitted mass (kg); mm is a dummy cumulative emitted-mass coordinate (kg); U(m)U(m) is the same outlet-speed history reparameterized by discharged mass (m/s); Ej,E0E_j,E_0 are emitted energy and available work (J); AobsA_{\mathrm{obs}} is positive observer area (m²); τobs\tau_{\mathrm{obs}} is positive averaging time (s); pˉarrest\bar p_{\mathrm{arrest}} is mean positive arrest pressure attributable to these emitted parcels (Pa).

Ij2=(∫0mjU(m)dm)2≤(∫0mj1dm)(∫0mjU(m)2dm)=2mjEj≤2mjE0,pˉarrest≤Ij/(Aobsτobs).\begin{aligned} I_j^2&=\left(\int_0^{m_j}U(m)dm\right)^2 \le\left(\int_0^{m_j}1dm\right)\left(\int_0^{m_j}U(m)^2dm\right) =2m_jE_j\le2m_jE_0,\\ \bar p_{\mathrm{arrest}}&\le I_j/(A_{\mathrm{obs}}\tau_{\mathrm{obs}}). \end{aligned}

Apply Cauchy–Schwarz to the integrable finite speed history. Its two integrals are emitted mass and twice emitted energy. Assume parcels stop without reversal and receive no extra actuation. Their received impulse is then bounded by incoming impulse. Divide by specified area and duration for mean pressure. Defaults are outlet area and one microsecond. Instantaneous impact pressure remains uncomputed. Propagation and water hammer are excluded.

Eq. (E24) — matched single-event transmission measures.

Symbols before Eq. (E24): TU,TE,TI,TqT_U,T_E,T_I,T_q are dimensionless ratios; subscripts A,BA,B identify matched rigid and hydrogel cases with the same source state, density and outlet geometry; UA,max⁡,UB,max⁡U_{A,\max},U_{B,\max} are first-event outlet-speed maxima (m/s); Ej,A,Ej,BE_{j,A},E_{j,B} are emitted energies accumulated by each event endpoint (J); Ij,A,Ij,BI_{j,A},I_{j,B} are emitted impulses (N s); qj,A,max⁡,qj,B,max⁡q_{j,A,\max},q_{j,B,\max} are first-event dynamic-pressure maxima (Pa); denominators are positive in the rigid reference.

TU=UB,max⁡/UA,max⁡,TE=Ej,B/Ej,A,TI=Ij,B/Ij,A,Tq=qj,B,max⁡/qj,A,max⁡=TU2.T_U=U_{B,\max}/U_{A,\max},\quad T_E=E_{j,B}/E_{j,A},\quad T_I=I_{j,B}/I_{j,A},\quad T_q=q_{j,B,\max}/q_{j,A,\max}=T_U^2.

At equal density, dynamic-pressure ratio equals speed ratio squared. Integrate full histories for emitted energy and impulse. A peak speed cannot determine these integrals. Stop each open case at speed return, inventory exhaustion or validity screen. Matched cases may therefore have different endpoints. These ratios compare finite outputs per shot. They are distinct from frequency-domain transfer functions. Every emitted-output ratio is zero for a sealed channel.

Step 9 — Declare the regime and check its communication rate

Eq. (E25) — communication and Mach diagnostics.

Symbols before Eq. (E25): Cp,Mj,Mw\mathcal C_p,M_j,M_w are dimensionless diagnostics; LcommL_{\mathrm{comm}} is communication length (m), chosen as inertance length for A and the greater of inertance length and chamber diameter for B; cLc_L is reference speed (m/s); pbp_b is positive absolute pressure (Pa); p˙b\dot p_b is its time derivative (Pa/s); κ\kappa is dimensionless; Vg,V˙gV_g,\dot V_g are volume and its rate (m³, m³/s); U,WU,W are speeds (m/s); absolute values denote magnitudes.

Cp=LcommcL∣p˙b∣pb=LcommcLκ∣V˙g∣Vg,Mj=∣U∣cL,Mw=∣W∣cL.\mathcal C_p=\frac{L_{\mathrm{comm}}}{c_L}\frac{|\dot p_b|}{p_b} =\frac{L_{\mathrm{comm}}}{c_L}\frac{\kappa|\dot V_g|}{V_g},\qquad M_j=\frac{|U|}{c_L},\qquad M_w=\frac{|W|}{c_L}.

Logarithmically differentiate Eq. (E04) for the second communication expression. Compare pressure-change and pressure-communication times. No propagation field is solved. The open baseline communication diagnostic stays below 0.1. This is a stipulated screen, whose error bound remains unvalidated. Both Mach diagnostics must also stay below 0.1.

Undrained behavior requires events much shorter than solvent drainage. The course uses an illustrative 30 micrometer drainage scale. Its estimated drainage time is 1.5 s. These events last microseconds. Actual permeability and rate-dependent moduli remain unmeasured. Check small-outlet geometry, positive liquid inventory and intact gel. Check gas breakthrough before the finite stroke ends. The 20% stretch stop is a stipulated deformation screen. Measured fracture strain is missing.

Check the sealed case communication ratio separately. Energy conservation cannot resolve failed pressure communication. A pressure-history prediction requires that screen to pass.

What the completed models can establish

The models provide conditional first-event solutions and maxima. They derive energy ceilings, spherical gel resistance and recoverable work. They also calculate matched finite-output ratios. A universal cavitation maximum is not established. Calibrated PFC limits and the excluded 10 ns activation pressure remain unresolved. Collapse-jet maxima and transmission through intact gel also remain unresolved.

Experimental validation requires post-activation phase volume and pressure. A measured pressure-volume path can supply the source work. Record absorbed pulse energy and conversion evidence. Specify moving liquid mass, outlet geometry and channel status. Measure gel modulus and viscosity at the event strain rate. Measure cavity volume, emitted speed, mass and wall deformation together. Declare comparison locations and averaging intervals. Compare source pressure, dynamic pressure and all four finite-output ratios.